BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

If (x+y)/z = -2, is x positive?

Expert replies
Source: — Data Sufficiency |

by Jay@ManhattanReview » Tue Jul 31, 2018 12:14 am
BTGmoderatorDC wrote:If (x+y)/z = -2, is x positive?

(1) z is negative.
(2) y is positive.
Given: (x+y)/z = -2

Question: Is x positive?

Let's take each statement one by one.

(1) z is negative.

We have (x+y)/z = -2 => (x+y) = -2*-|z| => (x+y) = 2|z| => (x+y) = Positive

x can be positive, 0 or negative. Insufficient.

(2) y is positive.

We have (x+y)/z = -2 => x + |y| = -2z => x = -|y| - 2z

Depending on the value of z, x can be negative, 0 or positive. Insufficient.

(1) and (2) together

We have (x+y)/z = -2 =>x + |y| = -2*-|z| => x = -|y| + 2|z|

Depending on the value of y, x can be negative, 0 or positive. Insufficient.

The correct answer: E

Hope this helps!

-Jay
_________________
Manhattan Review

Locations: Manhattan Review Bangalore | GMAT Prep Chennai | GRE Prep Himayatnagar | Hyderabad GRE Coaching | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.
Join the discussion

by ceilidh.erickson » Wed Aug 01, 2018 6:37 am
BTGmoderatorDC wrote:If (x+y)/z = -2, is x positive?

(1) z is negative.
(2) y is positive.
First, REPHRASE the question to determine what kind of information we need for sufficiency.

If a fraction is equal to a negative number, then either then numerator is negative and the denominator positive, or vice versa. In order for x to be positive, the entire numerator (x + y) could be positive and z could be negative, or (x + y) could be negative and z positive.

(1) z is negative.
This tells us that our denominator is negative, so the numerator (x + y) must be positive. However, y could be a larger positive and x could be negative, and we'd still have a positive numerator overall. Without information about y, this is insufficient.

(2) y is positive.
This tells us very little. x and y might both be positive and z negative, or z positive and x a negative with a larger absolute value than y. Insufficient.

(1) and (2) together
We know that z is negative, so the numerator (x + y) must be positive. And we're also given that y must be positive. But does x need to be positive? Test some values:

Case 1: x and y both positive, z negative
$$\frac{1+3}{-2}=-2$$

Case 2: x negative, y positive, z positive
$$\frac{-1+5}{-2}=-2$$

Since we can come up with negative and positive values for x that fit the givens, both statements together are insufficient.

The answer is E.
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education
Join the discussion