Unable to understand the solution, help please !

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Given that the mean of Set A is 10, what is the range of two standard deviations above and below the mean?

(1) One standard deviation above and below the mean ranges from 7 to 13.

(2) The median of set A is 11.

The answer to this is statement 1 by itself is sufficient and not 2 by itself. Any explanations please ?
Source: — Data Sufficiency |

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by GMATGuruNY » Sun Dec 11, 2016 3:29 am
aditiniyer wrote:Given that the mean of Set A is 10, what is the range of two standard deviations above and below the mean?

(1) One standard deviation above and below the mean ranges from 7 to 13.

(2) The median of set A is 11.
Statement 1:
7 is one SD below the mean of 10.
13 is one SD above the mean of 10.
The result is the following:
7-----10-----13
Since 7 is 3 places below the mean and 13 is 3 places above the mean, SD=3.
Thus:
2 SDs below the mean is 3 places to the left of 7.
2 SDs above the mean is 3 places to the right of 13.
The result is the following:
4-----7-----10-----13-----16
Range of the two values in blue = 16-4 = 12.
SUFFICIENT.

Statement 2:
Given the mean and median of set A, we cannot determine the set's SD.
INSUFFICIENT.

The correct answer is A.
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by aditiniyer » Sun Dec 11, 2016 5:29 am
Hey,

Thanks a ton.The explanation was lucid :)

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by Jay@ManhattanReview » Mon Dec 12, 2016 10:55 pm
aditiniyer wrote:Given that the mean of Set A is 10, what is the range of two standard deviations above and below the mean?

(1) One standard deviation above and below the mean ranges from 7 to 13.

(2) The median of set A is 11.

The answer to this is statement 1 by itself is sufficient and not 2 by itself. Any explanations please ?
We are given that mean = X = 10. Say SD = p

Value below 2SD = X - 2p;

Value above 2SD = X + 2p

Thus, range of values 2SD above and 2SD below the mean = [X + 2p] - [X - 2p] = 4p

So if we know the value of p, we get the answer.

S1: Range of values 1SD above and 1SD below the mean [X + p] - [X - p] = 2p = 13 - 7 = 6

=> Range of values 2SD above and 2SD below the mean = 4p = 2*6 12. SUFFICIENT!

S2: We need a way out to get the value of SD; knowing the values of mean and median will not help.

OA: A

Hope this helps!

-Jay

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