Poisson wrote:

A framed picture is shown above. The frame, shown shaded, is 6 inches wide and forms a border of uniform width around the picture. What are the dimensions of the viewable portion of the picture?

1. The area of the shaded region is 24 square inches.
2. The frame is 8 inches tall.

Statement 1:
shaded region = total area - picture area.
Thus:
total area - picture area = 24.

Case 1: frame width = 1 inch

In this case:
total area = 6h.
picture area = (4)(h-2).
Since total area - picture area = 24, we get:
6h - (4)(h-2) = 24
6h - 4h + 8 = 24
2h = 16
h = 8.
height of the picture = h-2 = 8-2 = 6.
width of the picture = 4.

Case 2: frame width = 0.5 inch

In this case:
total area = 6h.
picture area = (5)(h-1).
Since total area - picture area = 24, we get:
6h - (5)(h-1) = 24
6h - 5h + 5 = 24
h = 19.
height of the picture = h-1 = 19-1 = 18.
width of the picture = 5.

Since the picture can take on different dimensions, INSUFFICIENT.

Statement 2:
Case 1 also satisfies Statement 2.
In Case 1:
height of the picture = 6.
width of the picture = 4.

Case 3:

In this case:
Height of the picture = 4.
Width of the picture = 2.

Since the picture can take on different dimensions, INSUFFICIENT.

Statements combined:
Only Case 1 satisfies both statements.
In Case 1:
height of the picture = 6.
width of the picture = 4.
SUFFICIENT.

The correct answer is C.