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A number of individuals volunteer to walk dogs at a certain kennel this afternoon. The kennel's dogs...

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by BTGmoderatorLU » Mon May 25, 2020 5:53 am

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Source: Veritas Prep

A number of individuals volunteer to walk dogs at a certain kennel this afternoon. The kennel's dogs number between 43 and 47, inclusive. If each dog is walked by only one volunteer this afternoon, can the dogs be divided equally among the volunteers?

1) More than 5 individuals volunteer to walk the dogs.
2) Fewer than 8 individuals volunteer to walk the dogs.

The OA is C
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Source: — Data Sufficiency |

BTGmoderatorLU wrote:
Mon May 25, 2020 5:53 am
Source: Veritas Prep

A number of individuals volunteer to walk dogs at a certain kennel this afternoon. The kennel's dogs number between 43 and 47, inclusive. If each dog is walked by only one volunteer this afternoon, can the dogs be divided equally among the volunteers?

1) More than 5 individuals volunteer to walk the dogs.
2) Fewer than 8 individuals volunteer to walk the dogs.

The OA is C
So, the number of dogs are one among 43, 44, 45, 46, and 47.

Let's take each statement one by one.

1) More than 5 individuals volunteer to walk the dogs.

Case 1: Say no. of volunteers = 6, then we see that none of the numbers 43, 44, 45, 46, and 47 is completely divisible by 6. The answer is No.

Case 2: Say no. of volunteers = 15, then we see that 45 is completely divisible by 7. The answer is yes.

No unique answer. Insufficient.

2) Fewer than 8 individuals volunteer to walk the dogs.

Case 1: Say no. of volunteers = 7, then we see that none of the numbers 43, 44, 45, 46, and 47 is completely divisible by 7. The answer is No. Insufficient.

Case 2: Say no. of volunteers = 5, then we see that 45 is completely divisible by 5. The answer is yes.

No unique answer. Insufficient.

(1) and (2) together

From both the statements, we have no. of volunteers = 6 or 7.

We have already seen that none of the numbers 43, 44, 45, 46, and 47 is completely divisible by 6 or 7. The answer is No. Sufficient.

The correct answer: C

Hope this helps!

-Jay
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