(1) 7^(x+1) > 16,500M7MBA wrote:Is 7^x greater than 2,500?
(1) 7^(x+1) > 16,500
(2) 7^(x+2) = 7^x + 16464
The OA is B.
How can I use statement (2) to get an answer? I don't know how to solve this DS question.
=> (7^x)*7 > 16500
(7^x) > 16500/7
7^x > 2357...
Case 1: If 2500 ≥ 7^x > 2357..., the answer is No.
Case 2: If 7^x > 2500, the answer is Yes. No unique answer. Insufficient.
(2) 7^(x+2) = 7^x + 16464
7^(x+2) - 7^x = 16464
(7^x)*7^2 - 7^x = 16464
7^x(7^2 - 1) = 16464
(7^x)*48 = 16464
7^x = 16464/48 = 343
Since 7^x = 343, we have 7^x is not greater than 2500. The answer is No. Sufficient.
The correct answer: B
Hope this helps!
-Jay
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