BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Gmat Prep Toughie

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Data Sufficiency |
Legendary Member
Posts: 1337
Joined: Sat Dec 27, 2008 6:29 pmFollowed by: 10 members
Thanked: 127 times

by Night reader » Sun Feb 20, 2011 1:07 am
y is s and x is r, now rewrite everything --> s=3r+2 OR 3r+2-s=0

st(1) BECOMES ridiculously simple ( 3r+2-s)(4r+9-s) = 0 is Not Sufficient, because we have also (4r+9-s) can be 0
st(2) (4r-6-s)(3r+2-s) =0; (3r+2-s) =0 ? Not Sufficient

Combined st(1&2): both ( 3r+2-s)(4r+9-s) = 0 AND (4r-6-s)(3r+2-s) =0 can be zero if one of common factors is 0 (zero). Only possible with the ( 3r+2-s) = 0 why not Sufficient?

IOM C
Cheers
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 101
Joined: Thu Jan 06, 2011 12:44 am
Thanked: 1 times

by btgyes » Sun Feb 20, 2011 1:13 am
Night reader wrote:y is s and x is r, now rewrite everything --> s=3r+2 OR 3r+2-s=0

st(1) BECOMES ridiculously simple ( 3r+2-s)(4r+9-s) = 0 is Not Sufficient, because we have also (4r+9-s) can be 0
st(2) (4r-6-s)(3r+2-s) =0; (3r+2-s) =0 ? Not Sufficient

Combined st(1&2): both ( 3r+2-s)(4r+9-s) = 0 AND (4r-6-s)(3r+2-s) =0 can be zero if one of common factors is 0 (zero). Only possible with the ( 3r+2-s) = 0 why not Sufficient?

IOM C
Cheers

Thanks Dude..
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 8
Joined: Wed Feb 11, 2009 12:55 am

by kanhaiya » Sun Feb 20, 2011 5:09 am
nice explanation.. thnx Night reader
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1