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Harvey

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by fruti_yum » Sat Aug 01, 2009 7:58 pm
Harvey teaches a certain number of biology students in 2 classes, K and L. He can divide the students in class K into 7 groups of n students each. He can divide the students in class L into 6 groups of p students each with 1 student left over. How many students are in class L ?
(1) n = p
(2) There are 5 more students in class K than in class L.

I think it is B
oa IS c
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Source: — Data Sufficiency |
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by zeenab » Mon Aug 03, 2009 12:18 pm
Hi,

I thought the answer was B as well, but after looking at OA, I spent some more time on it.

With (2) there are more than 1 answers possible,

42 = 7*6 , 37 = 6*6+1 (which is the correct answer) and we can get this with (1) also.

but. consider

84 = 7*12, 79 = 6*13+1 -- this satisfies too. And unless we have (1)s aying n=p, we cannot center in on 42,37. which is the answer to the questions.

So OA = C is correct.
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by pralhadesh » Wed Aug 12, 2009 12:49 am
Harvey teaches a certain number of biology students in 2 classes, K and L. He can divide the students in class K into 7 groups of n students each. He can divide the students in class L into 6 groups of p students each with 1 student left over. How many students are in class L ?
(1) n = p
(2) There are 5 more students in class K than in class L.

Hi,

I solved it like this:

Given:

K = 7n and M = 6p + 1

From (1)

K = 7p and M = 6P + 1 ... NS

From (2)

K = L+5 ... NS

From 1 and 2

7p = (6p + 1) + 5... Sufficienet, Therefore C
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by vikram_k51 » Wed Aug 12, 2009 12:11 pm
Harvey teaches a certain number of biology students in 2 classes, K and L. He can divide the students in class K into 7 groups of n students each. He can divide the students in class L into 6 groups of p students each with 1 student left over. How many students are in class L ?
(1) n = p
(2) There are 5 more students in class K than in class L.


Should be C.
Solving gives n=p=6
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