Square wats given
a^3-a^2-b=49
a^2 (a-1) = b+49
Stmt I
a (a-1) = 12
a=-3 we can find a b value that satisfies the above condn
or
a=4 we can find a b value thats satisfies the above condn
INSUFF
Stmt II
b (b-1) = 2
b can be -1 or 2
If b= -1 we get a^2 (a-1) = b+49
a^2 (a-1) = 48
a=4
But when b=2 we get a^2 (a-1) = 51 (Not possible since a has to be an integer satisfying this condition 51 has 4 factors 1,3,17,51)
so a=4
hence b
integers
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