BTGmoderatorLU wrote:Source: Official Guide
If \(2^{4x}=3,600\), what is the value of \((2^{(1-x)})^2\)?
A. \(-\frac{1}{15}\)
B. \(\frac{1}{15}\)
C. \(\frac{3}{10}\)
D. \(-\frac{3}{10}\)
E. \(1\)
\((2^{(1-x)})^2\) = \(2^{2-2x}\) = \(2^2/2^{2x}\) = \(4/2^{2x}\)
We need to know the value of \(2^{2x}\):
\(2^{4x}=3,600\)
\((2^{2x})^2=3,600\)
\(2^{2x}= 60\)
Substituting \(2^{2x}= 60\) into \(4/2^{2x}\), we get:
4/60 = 1/15
The correct answer is
B.
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