Gmat_mission wrote:What is x?
(1) |x| < 2
(2) |x| = 3x - 2
Statement 1:
Here, x can be any value between -2 and 2.
INSUFFICIENT.
Statement 2:
Case 1: signs unchanged
x = 3x - 2
2 = 2x
1 = x
x = 1.
Case 2: signs changed in the absolute value
-x = 3x - 2
2 = 4x
2/4 = x
x = 1/2.
When an equation has absolute value only ON ONE SIDE, plug the two solutions back into the original equation to ensure that both are valid.
If we plug x=1 into |x| = 3x-2, we get:
|1| = 3*1 - 2
1 = 1.
This works.
x=1 is a valid solution for |x| = 3x-2.
If we plug x=1/2 into |x| = 3x-2, we get:
|1/2| = 3(1/2) - 2
1/2 = -1/2.
Doesn't work.
x=1/2 is NOT a valid solution for |x| = 3x-2.
Thus, Statement 2 has only one valid solution:
x=1.
SUFFICIENT.
The correct answer is
B.
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