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Root issues

by ganesh prasath » Mon Aug 01, 2011 6:27 pm
Hi all...can someone please explain me how to solve the 60th root of 8 the ans is twentieth root of 2.
similarly please tell me how to solve twentieth root of 2 whole power 10 the answer is root 2.

Thanks !........
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by vineeshp » Mon Aug 01, 2011 7:00 pm
(a raised to b) raised to c is equal to a raised to bc. (a^b)^c = a^bc
8^(1/60) = (2^3)^1/60 = 2 ^ (3 *1/60) = 2 ^ (1/20).

Now you can work out the other one yourself. (twentieth root is power to 1/20)[/b]
Vineesh,
Just telling you what I know and think. I am not the expert. :)
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by Anurag@Gurome » Mon Aug 01, 2011 7:05 pm
ganesh prasath wrote:Hi all...can someone please explain me how to solve the 60th root of 8 the ans is twentieth root of 2.
similarly please tell me how to solve twentieth root of 2 whole power 10 the answer is root 2.

Thanks !........
60th root of 8 = (8)^(1/60) = (2^3)^(1/60) = 2^(3*1/60) = 2^(1/20), which is the twentieth root of 2.
twentieth root of 2 whole power 10 = (2^10)^(1/20) = 2^(10*1/20) = 2^(1/2) = √2
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