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by mkhanna » Thu Aug 27, 2009 11:19 am
Q) A certain clock marks every hour by striking a number of times equal to the hour, and the time required for a stroke is exactly equal to the time interval between strokes. At 6:00 the time elapsed between the beginning of the first stroke and the end of the last stroke is 22 seconds. At 12:00, how many seconds elapse between the beginning of the first stroke and the end of the last stroke?

a) 72
b) 50
c) 48
d) 46
e) 44
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Source: — Problem Solving |

by m&m » Thu Aug 27, 2009 11:47 am
so there will be a time to "ding" and a time for the lag between "ding"s. So let's call ding time x and lag time y

example given is 22 seconds for 6 dings from begining of first ding to end of last ding. This means we will have 5 lags between each ding.

so 6x+5y = 22 sec

we are told dings and lag times are equal so x=y

6x+5x=22
so x=2

now question asks us for time elapsed at 12
so 12 dings and 11 lags or = 12x + 11x = 23x = 23(2) = 46 seconds

so answer is d

hope this helps
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by bharathh » Thu Aug 27, 2009 12:15 pm
I get the same answer. Did it the following way

|=stroke _ = interval

For 6:00
|_|_|_|_|_| = 11 total events in 22 seconds.. 1 event = 2 secs

For 12:00, there will be 23 events
So 23 x 2 = 46 s
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by mkhanna » Fri Aug 28, 2009 8:22 am
Thanks guys. Very helpful. 46 is the right answer. :)
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