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If r = 0.345, s = (0.345)^2, and t = sqrt(0.345) , which

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by VJesus12 » Sun Apr 14, 2019 9:50 am

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Answers

A

B

C

D

E

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Difficulty—

If $$r=0.345,\ \ \ \ \ s=\left(0.345\right)^2\ \ \ \ and\ \ \ \ \ \ t=\sqrt{0.345},$$ which of the following is the correct ordering of r, s, and t ?

A. r < s < t
B. r < t < s
C. s < t < r
D. s < r < t
E. t < r < s

[spoiler]OA=D[/spoiler]

Source: Official Guide
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by Vincen » Sat Apr 20, 2019 4:08 am
If $$r=0.345,\ \ \ \ \ s=\left(0.345\right)^2\ \ \ \ and\ \ \ \ \ \ t=\sqrt{0.345},$$ which of the following is the correct ordering of r, s, and t ?

A. r < s < t
B. r < t < s
C. s < t < r
D. s < r < t
E. t < r < s

[spoiler]OA=D [/spoiler]

Source: Official Guide
Hi Vjesus12.

Here, we need to use the following fact:

if \( x \) is a positive number less than 1, \((0 < x < 1)\) then \(0 < x^2 < x < \sqrt{x}<1.\)

Using this we can easily conclude that the correct order for the given 3 number is \( s < r < t. \)

This is why the correct answer is the option _D_.

I hope it helps you. <i class="em em---1"></i>
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by Scott@TargetTestPrep » Fri Apr 26, 2019 2:33 pm
VJesus12 wrote:If $$r=0.345,\ \ \ \ \ s=\left(0.345\right)^2\ \ \ \ and\ \ \ \ \ \ t=\sqrt{0.345},$$ which of the following is the correct ordering of r, s, and t ?

A. r < s < t
B. r < t < s
C. s < t < r
D. s < r < t
E. t < r < s

[spoiler]OA=D[/spoiler]

Source: Official Guide
Since 0.345 is between 0 and 1, we know that when it is squared, the value decreases and when it is square rooted, the value increases. Thus:

s < r < t

Answer: D

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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