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the scout leader

by sanju09 » Mon Mar 26, 2012 12:56 am
If five more scouts are added to a scout camp group, would the scout leader be able to divide the group into teams of 10 scouts each without any remainder?
(1) Initially, the number of scouts in the group was not divisible by ten.
(2) If 25 scouts are added to the group, the group can be divided into teams of 10 without any remainder.
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by seal4913 » Mon Mar 26, 2012 2:28 pm
I would have to say B.

As statement 1 says the orginal number isn't divisible by 10. So say 15 and add 5 then it is. But if it's 11 and add 5 then it isn't.

statement 2 you are adding 25. So if you have 15 and add 25 then it's 40 and meets the factor and then 15 plus 5 is divisible by 10. This would work with any number that you could start with that makes it divisible by 10. So i started with 25 and 25 that's 50; then 25 plus 5 is 30 fits.

Am i right?
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by sanju09 » Tue Mar 27, 2012 1:29 am
seal4913 wrote:I would have to say B.

As statement 1 says the orginal number isn't divisible by 10. So say 15 and add 5 then it is. But if it's 11 and add 5 then it isn't.

statement 2 you are adding 25. So if you have 15 and add 25 then it's 40 and meets the factor and then 15 plus 5 is divisible by 10. This would work with any number that you could start with that makes it divisible by 10. So i started with 25 and 25 that's 50; then 25 plus 5 is 30 fits.

Am i right?
Yes, you are right, seal4913. Just keep it up!
The mind is everything. What you think you become. -Lord Buddha



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by sam2304 » Tue Mar 27, 2012 2:10 am
IMO B.

same approach as explained by seal
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