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Re: Solve

by Scott@TargetTestPrep » Sat Jun 20, 2020 2:41 pm
Gmat_mission wrote: ↑
Sun Jun 14, 2020 2:20 pm
 \(\dfrac{49^3−147}{49}= \)

A. 1654
B. 1977
C. 2045
D. 2398
E. 2401

[spoiler]OA=D[/spoiler]

Solution:

Note that 147 = 49 * 3. Simplifying, we have:

49(49^2 - 3)/49

49^2 - 3

2401 - 3

2398

Answer: D

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