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Area of a triangle with coordinates provided

Expert replies
by topspin360 » Sat Jun 30, 2012 7:06 pm
Is there any way to solve this problem without creating a graph? Any simple way that can be used in under 2 minutes?

thanks

What is the area of a triangle with the following vertices L(1,3), M(5,1), and N(3,5)?
3
4
5
6
7
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Source: — Problem Solving |

by Anurag@Gurome » Sat Jun 30, 2012 7:35 pm
topspin360 wrote:What is the area of a triangle with the following vertices L(1,3), M(5,1), and N(3,5)?
If you are good with calculation and remembering formulas, you can easily solve this problem.

The area of triangle formed by the coordinates (x1, y1), (x2, y2), and (x3, y3) is given by
  • A = |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|/2
Hence, area of the triangle = |1*(1 - 5) + 5*(5 - 3) + 3*(3 - 1)|/2 = |-4 + 10 + 6|/2 = 12/2 = 6

The correct answer is D.
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by topspin360 » Sat Jun 30, 2012 8:06 pm
yessir, pretty good at remembering. thanks!
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by GMATinsight » Fri Sep 30, 2016 7:03 pm
topspin360 wrote:Is there any way to solve this problem without creating a graph? Any simple way that can be used in under 2 minutes?

thanks

What is the area of a triangle with the following vertices L(1,3), M(5,1), and N(3,5)?
3
4
5
6
7
Please find attached the two solutions.
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Solution GMATinsight.jpg
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by Brent@GMATPrepNow » Sat Oct 01, 2016 7:51 am
Now that you know the technique, you can practice your speed with this one: https://www.beatthegmat.com/coordinate-g ... 16975.html

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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