BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Integer Question - Looking for values for K

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Newbie | Next Rank: 10 Posts
Posts: 9
Joined: Wed May 01, 2013 10:04 pm
by jkcm25 » Fri May 24, 2013 7:18 pm
Q: If "K" is an integer and 3 is the remainder when K is divided by 5, how many values for K are possible when 0<k<100?

I thought the answer was "19", and it turns out to be "20". Could someone explain to me why the smallest value for K is "3"?
I started my lowest value for K as 8 where 8 / 5 = remainder 3.

How is it possible that K's lowest value could equal to "3" when clearly 3 / 5 does not yield to an integer answer with the remainder 3? Could someone refute my obvious flawed reasoning?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Legendary Member
Posts: 512
Joined: Mon Jun 18, 2012 11:31 pmFollowed by: 20 members
Thanked: 42 times

by sana.noor » Fri May 24, 2013 7:40 pm
its 20, start with 3 and then 8. 3 will be the smallest value and you can divide it as 0/5 = (5)(0) + 3. 3 is the remainder when divided by 5. it means in every 10 natural numbers their are 2 such numbers. less than 100 means that the last number will be 98. therefore, (2)(10) = 20
Work hard in Silence, Let Success make the noise.

If you found my Post really helpful, then don't forget to click the Thank/follow me button. :)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 9
Joined: Wed May 01, 2013 10:04 pm

by jkcm25 » Fri May 24, 2013 7:50 pm
Hi sorry, this did not really answer my question why the lowest value for K = 3.
I understand the subsequent integer answers STARTING from "K" integers: 8,13,18,..... up to 98 when these "K" integers are divided 5 it yields 3 as a remainder.

How is it that K integer "3" when divided by "5" could yield a remainder of "3"? So 3 divided 5= integer, Remainder 3???
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 9
Joined: Wed May 01, 2013 10:04 pm

by jkcm25 » Fri May 24, 2013 7:57 pm
I've skimmed your answer so fast. I missed your point. Thanks!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 512
Joined: Mon Jun 18, 2012 11:31 pmFollowed by: 20 members
Thanked: 42 times

by sana.noor » Fri May 24, 2013 9:23 pm
5 multiply by 0 will lead to answer 0...Remember: 0 is the multiple of every number thus u can divide 3 with 5. 3/5 = (5)(0) + 3...so include 3 and the right answer is 20
Work hard in Silence, Let Success make the noise.

If you found my Post really helpful, then don't forget to click the Thank/follow me button. :)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 9
Joined: Wed May 01, 2013 10:04 pm

by jkcm25 » Sat May 25, 2013 3:07 pm
Thanks for the clarification. I got it :)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members
Location: Vancouver, BC
Thanked: 5254 times
GMAT Score:770

by Brent@GMATPrepNow » Sun May 26, 2013 4:58 am
jkcm25 wrote:Q: If "K" is an integer and 3 is the remainder when K is divided by 5, how many values for K are possible when 0<k<100?

I thought the answer was "19", and it turns out to be "20". Could someone explain to me why the smallest value for K is "3"?
I started my lowest value for K as 8 where 8 / 5 = remainder 3.

How is it possible that K's lowest value could equal to "3" when clearly 3 / 5 does not yield to an integer answer with the remainder 3? Could someone refute my obvious flawed reasoning?
Most students are good a listing some possible values that satisfy given information regarding remainders. However, they often miss the smallest possible value (in this case the value of 3)

When it comes to remainders, we have a nice rule that says:

If N divided by D, leaves remainder R, then the possible values of N are R, R+D, R+2D, R+3D,. . . etc.

For example, if k divided by 5 leaves a remainder of 1, then the possible values of k are: 1, 1+5, 1+(2)(5), 1+(3)(5), 1+(4)(5), . . . etc.

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1