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Few more permutations/combination questions

Problem Solving — algebra and arithmetic (GMAT Focus Edition)
Expert replies
by fangtray » Tue Sep 20, 2011 3:54 am
1. In how many ways can 5 rings be worn on the four fingers of the right hand?

2. Three math books, four english books, and four reasoning books are kept on a shelf. In how many ways can they be arranged so that the books of each type are always together?

3. How many 3 letter words can be constructed using all the 26 letters of the english alphabet if only the middle letter of each word is a vowel?

4. In how many ways can 5 identical black balls and 7 identical white balls be arranged in a row so that no 2 black balls are together?

5. In how many ways can all the 7 sweets be distributed to three friends Jack, Jill, and John so that Jill alway sgets 2 sweets and each of them gets at least one sweet?

6. In how many ways can 4 men and 4 women sit at a round table with no two women in a consectuive position?

7. In how many ways can one choose 6 cards from a normal deck of cards so as to have all suits present?
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Source: — Quantitative Reasoning |

by cans » Tue Sep 20, 2011 4:14 am
1. In how many ways can 5 rings be worn on the four fingers of the right hand?
Assuming one finger can have all the 5 rings: 4^5. (4*4*4*4*4)
2. Three math books, four english books, and four reasoning books are kept on a shelf. In how many ways can they be arranged so that the books of each type are always together?

3!*3!*4!*4!
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by cans » Tue Sep 20, 2011 4:16 am
3. How many 3 letter words can be constructed using all the 26 letters of the english alphabet if only the middle letter of each word is a vowel?

for the middle letter: 5 options.
21 consonants.
21*5*21 (its not mentioned that letters can't be repeated)
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by cans » Tue Sep 20, 2011 4:19 am
4. In how many ways can 5 identical black balls and 7 identical white balls be arranged in a row so that no 2 black balls are together?


arrange 7 white balls: 1 way.
no. of gaps = 8
pick any 5 spaces and put black balls. 8C5.
Arrange them:1
thus 8C5
5. In how many ways can all the 7 sweets be distributed to three friends Jack, Jill, and John so that Jill alway sgets 2 sweets and each of them gets at least one sweet?
7C2 (for Jill) * (2^5 - 1 -1) (2^5 because each of the sweet can be given to any of the 2 persons.
-1 and -1 because in case all the sweets given to only Jack or to only John)
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by cans » Tue Sep 20, 2011 4:20 am
6. In how many ways can 4 men and 4 women sit at a round table with no two women in a consectuive position?

arrange 4 men: 3! (round table)
Now 4 spaces and 4 women: 4!
3!*4!
7. In how many ways can one choose 6 cards from a normal deck of cards so as to have all suits present?
13^4 * 48C2
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by fangtray » Tue Sep 20, 2011 5:35 am
cans wrote:
1. In how many ways can 5 rings be worn on the four fingers of the right hand?
Assuming one finger can have all the 5 rings: 4^5. (4*4*4*4*4)
2. Three math books, four english books, and four reasoning books are kept on a shelf. In how many ways can they be arranged so that the books of each type are always together?

3!*3!*4!*4!
why do you do that for #2? how do you come up with your answers ?
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by cans » Tue Sep 20, 2011 7:08 am
fangtray wrote:
cans wrote:
1. In how many ways can 5 rings be worn on the four fingers of the right hand?
Assuming one finger can have all the 5 rings: 4^5. (4*4*4*4*4)
2. Three math books, four english books, and four reasoning books are kept on a shelf. In how many ways can they be arranged so that the books of each type are always together?

3!*3!*4!*4!
why do you do that for #2? how do you come up with your answers ?
as books of each type are together, let bundle be: M,E,R.
Thus 3! ways to arrange the bundles.
Now internally in the bundles, the books can be arranged.
Maths 3! and so on...
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by arslanoqads » Thu Sep 05, 2013 5:10 am
cans wrote:
4. In how many ways can 5 identical black balls and 7 identical white balls be arranged in a row so that no 2 black balls are together?


arrange 7 white balls: 1 way.
no. of gaps = 8
pick any 5 spaces and put black balls. 8C5.
Arrange them:1
thus 8C5
5. In how many ways can all the 7 sweets be distributed to three friends Jack, Jill, and John so that Jill alway sgets 2 sweets and each of them gets at least one sweet?
7C2 (for Jill) * (2^5 - 1 -1) (2^5 because each of the sweet can be given to any of the 2 persons.
-1 and -1 because in case all the sweets given to only Jack or to only John)
hey cans, are you considering the sweets different in question 5?
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