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Vincen
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There is a set of beads, each of which is painted either red or blue. The beads are split, with each bead being cut in half. Then they are merged, where all the halves are randomly reassembled back into the same number of beads that there were, to begin with. This results in \(r\) red beads, \(b\) blue beads, and \(p\) beads that are half red and half blue. Before the split and merge, were there more red beads than blue beads?
(1) after the split and merge, the probability of picking a bead that is only red is less than the probability of picking a bead that is at least half blue.
(2) After the split and merge, the probability of picking a bead that is only blue is greater than the probability of picking a bead that is at least half red.
[spoiler]OA=B[/spoiler]
Source: Princeton Review
(1) after the split and merge, the probability of picking a bead that is only red is less than the probability of picking a bead that is at least half blue.
(2) After the split and merge, the probability of picking a bead that is only blue is greater than the probability of picking a bead that is at least half red.
[spoiler]OA=B[/spoiler]
Source: Princeton Review
