BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Least possible value of r+s

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 641
Joined: Tue Feb 14, 2012 3:52 pmFollowed by: 8 members
Thanked: 11 times
by gmattesttaker2 » Sat Feb 22, 2014 12:08 am
Hello,

Can you please assist with this:

lf r and s are positive integers, each greater than 1 and if 11(s - l) = l3(r - l), what is the least possible value of r + s?

A) 2
B) 11
C) 22
D) 24
E) 26

OA: E


I tried to solve this as follows:

11(s - l) = l3(r - l)

=> 11s - 11 = 13r - 13
=> -11 + 13 = 13r - 11s
=> 2 = 13r - 11s

Given r,s > 1

I then started testing the answer choices as follows:

Let, r + s = 22 => r = 22 - s

So, 11 ( s - 1 ) = 13 ( 22 - s - 1)
=> 11s - 11 = 13 ( 21 - s )
=> 11s - 11 = 273 - 13s
=> 11s + 13s = 273 + 11
=> 24s = 284
=> s = 284/24 = not an integer

Hence, r + s cannot be 22

I was wondering if there is a better way to solve this problem?

Thanks a lot,
Sri
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Master | Next Rank: 500 Posts
Posts: 490
Joined: Thu Jul 04, 2013 7:30 amFollowed by: 5 members
Location: Chennai, India
Thanked: 83 times

by Uva@90 » Sat Feb 22, 2014 1:47 am
gmattesttaker2 wrote:Hello,

Can you please assist with this:

lf r and s are positive integers, each greater than 1 and if 11(s - l) = l3(r - l), what is the least possible value of r + s?

A) 2
B) 11
C) 22
D) 24
E) 26

OA: E


I tried to solve this as follows:

11(s - l) = l3(r - l)

=> 11s - 11 = 13r - 13
=> -11 + 13 = 13r - 11s
=> 2 = 13r - 11s

Given r,s > 1

I then started testing the answer choices as follows:

Let, r + s = 22 => r = 22 - s

So, 11 ( s - 1 ) = 13 ( 22 - s - 1)
=> 11s - 11 = 13 ( 21 - s )
=> 11s - 11 = 273 - 13s
=> 11s + 13s = 273 + 11
=> 24s = 284
=> s = 284/24 = not an integer

Hence, r + s cannot be 22

I was wondering if there is a better way to solve this problem?

Thanks a lot,
Sri
Sri,
You ended up here,
13r - 11s = 2 => r+s +12r-12s =2 => r+s +12(r-s) =2
=> r+s = 2+12(s-r) => 2(1+6(s-r))

r+s = 2(1+6 (s-r) )

Let S-r = 0
r+s =2. But Question States that both r ans are greater than 1 hence their sum must be >2 REJECTED

Let S-r =1
r+s = 2(1+ 6(1)) =14 But Not in option. REJECTED.

Let S-r =2
r+s = 2(1+ 6(2)) = 26.YES it is there
Hence ans is E

Regards,
Uva.
Known is a drop Unknown is an Ocean
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Sat Feb 22, 2014 3:56 am
gmattesttaker2 wrote:Hello,

Can you please assist with this:

lf r and s are positive integers, each greater than 1 and if 11(s - l) = l3(r - l), what is the least possible value of r + s?

A) 2
B) 11
C) 22
D) 24
E) 26

OA: E
11(s - 1) = 13(r - 1) = x.
To minimize the values of r and s, we must minimize the value of x.
Since r and s are integers, x must be a multiple of the factors in red.
Thus, the least possible value for x = 11*13.
If x = 11*13, we get:

11(s-1) = 11*13
s-1 = 13
s=14.

13(r-1) = 11*13
r-1 = 11
r=12.

Thus, the least possible value for r+s = 12+14 = 26.

The correct answer is E.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1