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In a kickball competition of 9 teams, how many possible matches can each team play with each other?

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Re: In a kickball competition of 9 teams, how many possible matches can each team play with each other?

by Jay@ManhattanReview » Sun Mar 15, 2020 10:39 pm
BTGModeratorVI wrote: ↑
Sun Mar 15, 2020 12:38 pm
 In a kickball competition of 9 teams, how many possible matches can each team play with each other?

(A) 9
(B) 16
(C) 24
(D) 36
(E) 54

Answer: D
Source: GMAT Pill
Total no. of matches = 9C2 = 9.8/1.2 = 36

The correct answer: D

Hope this helps!

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Re: In a kickball competition of 9 teams, how many possible matches can each team play with each other?

by Brent@GMATPrepNow » Mon Mar 16, 2020 5:02 am
BTGModeratorVI wrote: ↑
Sun Mar 15, 2020 12:38 pm
 In a kickball competition of 9 teams, how many possible matches can each team play with each other?

(A) 9
(B) 16
(C) 24
(D) 36
(E) 54

Answer: D
Source: GMAT Pill
A DIFFERENT approach

If each of the 9 teams plays every team, then each team plays 8 games (since a team can't play itself)
So, the total number of games = (9)(8) = 72

From here we need to recognize that each game has been COUNTED TWICE.
For example, if Team A and Team B play a game, then Team A counts it as a game, and Team B ALSO counts it as a game.

So, to account for the DUPLICATION, we'll divide 72 by 2 to get 36

Answer: D

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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Re: In a kickball competition of 9 teams, how many possible matches can each team play with each other?

by Scott@TargetTestPrep » Tue Mar 17, 2020 9:06 am
BTGModeratorVI wrote: ↑
Sun Mar 15, 2020 12:38 pm
 In a kickball competition of 9 teams, how many possible matches can each team play with each other?

(A) 9
(B) 16
(C) 24
(D) 36
(E) 54

Answer: D
Source: GMAT Pill
The total possible number of matches is 9C2 = 9! / (2! x 7!) = (9 x 8) / 2 = 36.

Answer: D

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