Bob and Wendy

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 185
Joined: Thu Feb 04, 2010 3:06 am
Thanked: 6 times

Bob and Wendy

by gmatnmein2010 » Fri Feb 19, 2010 7:53 pm
Bob and Wendy planned to walk from their home to a restaurant for dinner together. However, Bob was delayed at work, and Wendy left for the restaurant before Bob did. If the restaurant is 3 miles from their home and Bob left for the restaurant a half-hour after Wendy did, how long did Wendy have to wait for Bob at the restaurant?

(1) Wendy walked at a constant pace of 4 miles per hour

(2) Bob walked at a constant pace of 1 mile per hour faster than Wendy.
Source: — Data Sufficiency |

User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pm
Location: Arabian Sea
Thanked: 125 times
Followed by:2 members

by ajith » Fri Feb 19, 2010 9:08 pm
gmatnmein2010 wrote:Bob and Wendy planned to walk from their home to a restaurant for dinner together. However, Bob was delayed at work, and Wendy left for the restaurant before Bob did. If the restaurant is 3 miles from their home and Bob left for the restaurant a half-hour after Wendy did, how long did Wendy have to wait for Bob at the restaurant?

(1) Wendy walked at a constant pace of 4 miles per hour

(2) Bob walked at a constant pace of 1 mile per hour faster than Wendy.
1) is not sufficient - we do not know the speed of Bob
2) is not sufficient - we do not know the speed of Wendy

Together we know the speed of Wendy y, Speed of Bob x
Wendy takes = 45 minutes to reach, bob takes 36 minutes , bob started 30 minutes late ..

Sufficient to calculate the waiting time
Always borrow money from a pessimist, he doesn't expect to be paid back.

User avatar
Legendary Member
Posts: 1560
Joined: Tue Nov 17, 2009 2:38 am
Thanked: 137 times
Followed by:5 members

by thephoenix » Fri Feb 19, 2010 10:16 pm
gmatnmein2010 wrote:Bob and Wendy planned to walk from their home to a restaurant for dinner together. However, Bob was delayed at work, and Wendy left for the restaurant before Bob did. If the restaurant is 3 miles from their home and Bob left for the restaurant a half-hour after Wendy did, how long did Wendy have to wait for Bob at the restaurant?

(1) Wendy walked at a constant pace of 4 miles per hour

(2) Bob walked at a constant pace of 1 mile per hour faster than Wendy.
from q t=3/B+1/2-3/W
where t is the waiting time for Wendy, B is the Bob's rate and W is the Wendy's rate.

hence in order to know t we require B and W

s1)b=? not given
insuff

s2)B=W+1
INSUFF AS WE DNT KNW W

Together
suff
as we have W and B

User avatar
Legendary Member
Posts: 1022
Joined: Mon Jul 20, 2009 11:49 pm
Location: Gandhinagar
Thanked: 41 times
Followed by:2 members

by shashank.ism » Sat Feb 20, 2010 10:20 pm
gmatnmein2010 wrote:Bob and Wendy planned to walk from their home to a restaurant for dinner together. However, Bob was delayed at work, and Wendy left for the restaurant before Bob did. If the restaurant is 3 miles from their home and Bob left for the restaurant a half-hour after Wendy did, how long did Wendy have to wait for Bob at the restaurant?

(1) Wendy walked at a constant pace of 4 miles per hour

(2) Bob walked at a constant pace of 1 mile per hour faster than Wendy.
ST.1 Wendy walked at a constant pace of 4 miles per hour so time taken by him = 3/4 = 45 minutes but nothing abt bob ==insufficient

St.2 Bob walked at a constant pace of 1 mile per hour faster than Wendy ... but we don't know the exact speed of both for time calculation =========insufficient

combined: speed of Bob = 4+1 = 5 miles per hour .... so, time taken by him = 3/5 = 36 minutes...
so wendy left half an hour earlier
Ans C
so he has to wait = 30 +45 -36 = 75 -36 = 39 minutes.. sufficient .
My Websites:
www.mba.webmaggu.com - India's social Network for MBA Aspirants

www.deal.webmaggu.com -India's online discount, coupon, free stuff informer.

www.dictionary.webmaggu.com - A compact free online dictionary with images.

Nothing is Impossible, even Impossible says I'm possible.