BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Of the 20 people who each purchased 2 tickets to a concert, some used both tickets, some used only 1 ticket, and some us

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Moderator
Posts: 2058
Joined: Sun Oct 29, 2017 4:24 am
Thanked: 1 times
Followed by:5 members

Of the 20 people who each purchased 2 tickets to a concert, some used both tickets, some used only 1 ticket, and some us

by M7MBA » Wed Sep 09, 2020 1:40 am

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

Of the 20 people who each purchased 2 tickets to a concert, some used both tickets, some used only 1 ticket, and some used neither ticket. What percent of the tickets that were purchased by the 20 people were used by those people?

(1) Of the 20 people, 10 used only 1 ticket.

(2) Of the 20 people, 4 used neither ticket.

Answer: C

Source: GMAT Prep
Top
Source: — Data Sufficiency |
Legendary Member
Posts: 2214
Joined: Fri Mar 02, 2018 2:22 pm
Followed by:5 members

Re: Of the 20 people who each purchased 2 tickets to a concert, some used both tickets, some used only 1 ticket, and som

by deloitte247 » Sun Sep 13, 2020 10:45 am

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

Let the number of people who used both tickets = b
Let the number of people who used one ticket = o
Let the number of people who used neither tickets = n
b + o + n = 20

Target question => What percent of the tickets that were purchased by the 20 people were used by those people?
$$i.e\ \frac{ticket\ used}{total\ tickets}\cdot\frac{100}{1}$$
$$\frac{2b+o}{20\cdot2}\cdot\frac{100}{1}$$
$$\frac{2b+o}{40}\cdot\frac{100}{1}$$

Statement 1 =>Of the 20 people, 10 used only 1 ticket i.e o = 10
$$\frac{2b+10}{40}\cdot100\ $$
But since the value of b is unknown, statement 1 is NOT SUFFICIENT

Statement 2 => Of the 20 people, 4 used neither ticket i.e n = 4
The value of b and o is unknown hence statement 2 is NOT SUFFICIENT

Combining both statements together =>
From statement 1 => o = 10
From statement 2 => n = 4
From question stem => b + o + n = 20
b + 10 + 4 = 20
b = 20 - 14 = 6
$$\%\ of\ used\ ticket\ =\frac{2\left(6\right)+10}{40}\cdot\frac{100}{1}$$
$$\frac{22}{40}\cdot\frac{100}{1}$$
$$=55\%$$
Both statements combined together ARE SUFFICIENT

Answer = C
Top
Post new topic Post Reply
• Page 1 of 1