This question comes down to finding three single digits that fit the parameters of the statements:
Statement 1: a = 1.5b and b = 1.5c
In order to get a digit when another digit is multiplied by 1.5, the digit being multiplied has to be even.
So we are down to 2, 4, 6 and 8 for digits b and c.
If a = 1.5b, and b = 1.5c, then a = 1.5²c = 2.25 c.
Of 2, 4, 6 and 8, the only one that can be used to generate a digit when multiplied by 2.25 is 4.
So a = 9.
b = 9/1.5 = 6
c = 6/1.5 = 4
So abc = 964
Sufficient.
Statement 2: a = 1.5x + b and b = x + c, where x represents a positive single digit.
Once again, in order for 1.5x to be an integer value, x has to be an even number, 2, 4, 6, or 8.
If a = 1.5x + b, and b = x + c, then a = 2.5x + c.
Since 2.5(4), 2.5(6) and 2.5(8) are all > 9, x can only be 2, and 2.5x = 5.
So we can start with any digit c and add 2 and 5 to it to get b and a.
Because 9 - 5 = 4, c ≤ 4.
So, for instance, abc could be 964 or 853.
Multiple values are possible.
Insufficient.
The correct answer is A.
