BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

P/S need help...

Expert replies
by metropia » Mon Mar 26, 2007 2:52 pm
Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?


A. m+4/m(m-4) B. 2m-4/m(m-4) C.4m-4/m(m-4) D. 4m-8/m(m-4)
E. 4m-12/m(m-4)


I tried to plug in the number (assume that m=12) ...can't get the right answer.
Join the discussion
Source: — Problem Solving |

by jayhawk2001 » Mon Mar 26, 2007 7:01 pm
First 3 sandwiches divided amongst m people, so each person gets 3/m
of the sandwich.

Last sandwich divided among m-4. So each person gets 1/(m-4)

So carol eats 3/m + 1/(m-4) = (4m-12) / (m(m-4))
Join the discussion

by Cybermusings » Wed Mar 28, 2007 6:38 am
Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?


A. m+4/m(m-4)
B. 2m-4/m(m-4)
C.4m-4/m(m-4)
D. 4m-8/m(m-4)
E. 4m-12/m(m-4)


This one seems easy...Lets hope I get it right

First 3 sandwiches divided amongst m students

Thus each student gets 3/m sandwich

Last sandwich divided amongst m - 4 students

Therefore each of those m-4 students gets 1/m-4 sandwich

Carol ate 3/m + 1/m-4 sandwich

= (3(m-4)+m)/m(m-4)

= 3m - 12 + m / m (m - 4)

= 4m - 12 / m (m - 4)

Hence E
Join the discussion

by Danny@GMATAcademy » Tue Jul 05, 2016 5:22 pm
Value substitution and algebra both work nicely for this question. See videos below:

Value substitution: https://youtu.be/L-fqOMzmglM

Algebra: https://youtu.be/usxNJ89lAZs

Hope they help.
Join the discussion

by OptimusPrep » Wed Jul 06, 2016 6:59 am
metropia wrote:Four extra-large sandwiches of exactly the same size were ordered for m students, where m > 4. Three of the sandwiches were evenly divided among the students. Since 4 students did not want any of the fourth sandwich, it was evenly divided among the remaining students. If Carol ate one piece from each of the four sandwiches, the amount of sandwich that she ate would be what fraction of a whole extra-large sandwich?


A. m+4/m(m-4) B. 2m-4/m(m-4) C.4m-4/m(m-4) D. 4m-8/m(m-4)
E. 4m-12/m(m-4)


I tried to plug in the number (assume that m=12) ...can't get the right answer.
Instead of number substituting, simple algebra would get you the answer quickly

3 sandwiches divided among m students.
Hence each student gets 3/m sandwiches

For the last one, 4 students do not want to eat, hence remaining students = m - 4
Each student gets 1/ (m-4) sandwiches

Total sandwiches eaten by Carol = 3/m + 1/(m-4) = 3m - 12 + m / m(m-4) = 4m-12/m(m-4)

Correct Option: E
Join the discussion

by Matt@VeritasPrep » Thu Jul 07, 2016 3:42 pm
Since the OP asked the question in 2007, I think we can assume the sandwiches are long spoiled, and there's no need to resurrect the thread.
Join the discussion