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GMAT Prep - geometry question

Expert replies
by mister_yogi » Mon Nov 03, 2008 7:21 pm
Can someone explain the answer to this? Is it the fact that if you draw a straight-line and form a right-triange, one side is the same and since <x is greater than <y, the other side has to be bigger resulting in a larger hyptonesue i.e PQ is > SR?

Thanks.
Last edited by mister_yogi on Tue Dec 09, 2008 1:54 pm, edited 1 time in total.
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Source: — Problem Solving |

by vishubn » Tue Nov 04, 2008 5:49 am
a) x>y , less the degree a line is angled away fro mthe 180 deg greter is the length of the line of the line formed !

so we know x>y

for example x=80deg, and y=60deg so deviation by 60deg line from 180 deg is less and the length from the line is more than the 80 deg line ! it holds good for all :)

b) x+y>90 it gives no inforation about the individual degrees so not sure

c) together!! again the same point as B

So A is the answer

Vishu
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by Hope700 » Tue Nov 04, 2008 8:49 am
Excelent answer
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by logitech » Tue Nov 04, 2008 9:02 am
The shortest distance between TWO parallel line is a line with 90 degrees.

The length of the line INCREASES when the angle DECREASES and once that angle is 0 you will have yourself another parallel line to other two lines and distance will be infinite.

So;

1) Sufficient because , if you know the angles, you can compare the distances

2) Insuf, because you actually dont know X and Y separately
LGTCH
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by vittalgmat » Tue Nov 04, 2008 12:24 pm
vishubn wrote:a) x>y , less the degree a line is angled away fro mthe 180 deg greter is the length of the line of the line formed !

so we know x>y

for example x=80deg, and y=60deg so deviation by 60deg line from 180 deg is less and the length from the line is more than the 80 deg line ! it holds good for all :)

b) x+y>90 it gives no inforation about the individual degrees so not sure

c) together!! again the same point as B

So A is the answer

Vishu
Excellent answer Vishu. However c is not necessary once u determine A is OK and B is not OK.

I am sure it was an oversight !! :-)
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by vishubn » Tue Nov 04, 2008 8:20 pm
Oh ya :)

I guess it was

Thanks

Vishu
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by jdkster » Wed Nov 05, 2008 7:12 am
Vishu,

the problem does not specify whether x is less or more than 90 degrees. so x can be more than 90. for instance x = 130, and y=80. clause 1 holds true, however we can't answer the question. thus, the conditions are of no help. answer is E

k
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by jdkster » Wed Nov 05, 2008 7:18 am
oops. it does specify that both are less than 90. my bad
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