worth commenting a little more on this one:
Gmatss wrote:1.) To satisfy this condition,
either x^3 is neg or (1-(x^2) is negative.
so, -1<x<0 or x>1 it can be positive or negative. so hence insuff
this is true inasmuch as "or" is used here in the sense of
exclusive "or". in other words,
exactly one of those two things must be true to satisfy the statement,
but not both.
a clearer way to express the result is:
x^3 and (1 - x^2) have opposite signs.
once you have the fact that x^3 is negative for x < 0 and positive for x > 0, as well as the fact that (1 - x^2) is negative for x < -1, x > 1 and positive for -1 < x < 1, the result follows.
Ron has been teaching various standardized tests for 20 years.
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