The formula is equal to:
3^(x-y)/3^(x+y) = 3^x/(3^(y)*3^(x)*3^(y)) = 1/(3^(2y)).
--> IMO B.
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equation
Source: Beat The GMAT — Data Sufficiency |
IMO A
3^-(x+y)/ 3^-(x-y)= 3^-x-y/3^-x+y
1. when x=2 it's 3^-2-y * 3^-2+y = 3^-4 as answer.
what is QA?
3^-(x+y)/ 3^-(x-y)= 3^-x-y/3^-x+y
1. when x=2 it's 3^-2-y * 3^-2+y = 3^-4 as answer.
what is QA?
oops read it wrong sorry qa should be B Thank youmental wrote:IMO B
gmatss: its a division sign and not multiplication
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There are a few ways to break this down. Three different approaches (there are surely others):beater wrote:What is the value of 3^-(x + y) / 3^-(x - y)?
(1) x = 2
(2) y = 3
-recall that 3^a/3^b = 3^(a-b) (when you have the same base in a division, you subtract the powers). We can use that here:
3^-(x + y) / 3^-(x - y) = 3^[ -(x+y) - (-(x-y))] = 3^[-x-y+x-y] = 3^(-2y)
So we only need to find y.
Alternatively you could use the fact that 3^(a+b) = [3^a][3^b]. Note that we can do this with any powers, negative or positive. You can expand the brackets and apply this:
3^-(x + y) / 3^-(x - y) = [3^(-x-y)/3^(y-x)] = [3^(-x)*3^(-y)]/[(3^y)*(3^(-x)]
Since the 3^(-x) term cancels, we only need y.
Or, you could use the fact that 3^(-a) = 1/3^a, so
3^-(x + y) / 3^-(x - y) = [1/(3^(x+y)]/[1/3^(x-y)] = [3^(x-y)]/[3^(x+y)]
and now that the potentially confusing minus signs are gone, it's easier to continue the problem using either of the methods above.
Each of the exponent rules I've used above is tested extensively on the GMAT, so each is worth understanding thoroughly.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com
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