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In a sequence of numbers in which each term after the first term is 1 more than twice the preceding term, what is the

Expert replies
by BTGmoderatorDC » Sun Dec 19, 2021 8:38 pm

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Answers

A

B

C

D

E

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Difficulty—

In a sequence of numbers in which each term after the first term is 1 more than twice the preceding term, what is the fifth term?

(1) The first term is 1.
(2) The sixth term minus the fifth term is 32.


OA D

Source: GMAT Prep
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Source: — Data Sufficiency |

BTGmoderatorDC wrote: ↑
Sun Dec 19, 2021 8:38 pm
In a sequence of numbers in which each term after the first term is 1 more than twice the preceding term, what is the fifth term?

(1) The first term is 1.
(2) The sixth term minus the fifth term is 32.


OA D

Source: GMAT Prep
Given: In a sequence of numbers in which each term after the first term is 1 more than twice the preceding term
Let's take a moment to see what this pattern looks like.
Let k = the term_1
So, we get:
term_1 = k
term_2 = 2k + 1
term_3 = 2(k + 1) + 1 = 2k + 3
term_4 = 2(2k + 3) + 1 = 4k + 7
term_5 = 2(4k + 7) + 1 = 8k + 15
term_6 = 2(8k + 15) + 1 = 16k + 31

So, term_5 = 8k + 15

Target question: What is term_5?

Statement 1: The first term is 1.
In other words, k = 1
Since we already determined that term_5 = 8k + 15, we can substitute to get: term_5 = 8(1) + 15 = 16 + 15 = 31
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: The sixth term minus the fifth term is 32
From our pattern we can see that term_5 = 8k + 15 and term_6 = 16k + 31
So, statement 2 is telling us that (16k + 31) - (8k + 15) = 32
Simplify the left side to get: 8k + 16 = 32
At this point, we can see that we COULD solve the equation for k, which means we COULD determine the value of term_5 the same way we did for statement 1 (although we would never waste valuable time on test day doing so)
Since we COULD answer the target question with certainty, statement 2 is SUFFICIENT

Answer: D

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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