If \(x\) is negative and \(y\) is positive, what is the value of \(x\) given that \(x^2-8xy+16y^2=49?\)

[Vincen]

If \(x\) is negative and \(y\) is positive, what is the value of \(x\) given that \(x^2-8xy+16y^2=49?\)

A. \(4y - 49\)
B. \(49 - 4y\)
C. \(-7 - 4y\)
D. \(7 + 4y\)
E. \(4y - 7\)

Answer: E

Source: Veritas Prep