Is AD > BC?

[BTGmoderatorDC]

Is AD > BC?

(1) CD = AB
(2) Angle CAB = Angle BCA


OA A

Source: e-GMAT

[rk_gmat]

Given:
Angles,
ADC = 90\({^0}\)
ABC = 90\({^0}\)
To find:
AD > BC ?

1) CD=AB
Therefore, it becomes a rectangle => AD = BC

SUFFICIENT

2) Angle, CAB = BCA
=> Triangle ABC is 45-90-45
=> \(AC\ =\sqrt{2}BC\ =\ \sqrt{2}\ AB\)
=> AD < \(\sqrt{BC}\)
but can't say AD < BC or not clearly

NOT SUFFICIENT

Choice: A