BTGModeratorVI wrote: ↑Thu Dec 03, 2020 2:50 pm
The sides of right triangle ABC are such that the length of side AB is greater than the length of side BC, which itself is greater than the length of side AC. If side AB = 143 and side AC = 55, what is the area of the triangle?
A. 3113
B. 3224
C. 3432
D. 3630
E. 7260
Answer:
D
Solution:
Since we are given that triangle ABC is a right triangle and AB is the longest side, so AB must be the hypotenuse of the triangle. Using the Pythagorean theorem, we have:
(AC)^2 + (BC)^2 = (AB)^2
55^2 + x^2 = 143^2
x^2 = 143^2 - 55^2
Noting that the right side of the equation is a difference of two perfect squares, we have:
x^2 = (143 + 55)(143 - 55)
x^2 = (198)(88)
x^2 = 2 * 99 * 8 * 11
x^2 = 16 * 9 * 11 * 11
x = √(16 * 9 * 11^2) = 4 * 3 * 11 = 132 = length of side BC
Since the area of a right triangle is half the product of the lengths of its two legs, the area of triangle ABC is ½ * AC * BC = ½ * 55 * 132 = 66 * 55 = 3630.
Answer: D
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