Arithmetic

[swerve]

If the sum of three consecutive integers is k, then which of the following is a possible value of k?

A. 199
B. 200
C. 201
D. 202
E. 203

The OA is C

Source: Magoosh

[psarma]

Let the 3 consecutive integers be n, n+1 and n+2
Given, n+(n+1)+(n+2)=k
or 3n+3=k
or 3(n+1)=k
i.e k is thus a multiple of 3.

From the options given, only 201 is a multiple of 3.

Answer C.

[Scott@TargetTestPrep]

If the sum of three consecutive integers is k, then which of the following is a possible value of k?

A. 199
B. 200
C. 201
D. 202
E. 203

The OA is C

Solution:

Since the sum of any three consecutive integers must be a multiple of 3 (e.g., 1 + 2 + 3 = 6; 8 + 9 + 10 = 27, etc.), then k could be 201 (notice that it’s the only number in the given choices that is a multiple of 3).

Answer: C