If \(x\) and \(y\) are both positive and \(\sqrt{x^2+y^2}=3x-y,\) then \(\dfrac{x}{y} =\)

[Gmat_mission]

If \(x\) and \(y\) are both positive and \(\sqrt{x^2+y^2}=3x-y,\) then \(\dfrac{x}{y} =\)

A. \(0\)
B. \(\dfrac14\)
C. \(\dfrac12\)
D. \(\dfrac34\)
E. \(\dfrac32\)

Answer: D

Source: Magoosh