If \(x>0\) and \(\sqrt{5x}=\sqrt{3x}+1,\) what is the value of \(4x^2?\)

[Vincen]

If \(x>0\) and \(\sqrt{5x}=\sqrt{3x}+1,\) what is the value of \(4x^2?\)

A. \(\dfrac12\)

B. \(1\)

C. \(4x-1\)

D. \(10x-1\)

E. \(16x-1\)

Answer: E

Source: Veritas Prep