Line J has a y-intercept of 6 and passes through point (a,b). What is the slope of Line J in terms of a and b?

[BTGmoderatorDC]

Line J has a y-intercept of 6 and passes through point (a,b). What is the slope of Line J in terms of a and b?

A. (a−6)/b
B. (a−b)/6
C. (6−a)/b
D. (6−b)/a
E. (b−6)/a



OA E

Source: Veritas Prep

[Scott@TargetTestPrep]

Line J has a y-intercept of 6 and passes through point (a,b). What is the slope of Line J in terms of a and b?

A. (a−6)/b
B. (a−b)/6
C. (6−a)/b
D. (6−b)/a
E. (b−6)/a



OA E

Solution:

We are given that line J has a y-intercept of 6. If we let m be the slope of line J, then the equation of line J, in slope-intercept form, is:

y = mx + 6

Since (a, b) is a point of line J, we have:

b = ma + 6

b - 6 = ma

(b - 6)/a = m

Answer: E