If \(n=\dfrac{2^{-10}+2^{-9}}{7^{-1}\cdot 5^9}\) then \(n\) is a terminating decimal with how many zeroes after the deci

[VJesus12]

If \(n=\dfrac{2^{-10}+2^{-9}}{7^{-1}\cdot 5^9}\) then \(n\) is a terminating decimal with how many zeroes after the decimal point before the first non-zero digit?

(A) 2

(B) 3

(C) 5

(D) 7

(E) 9

Answer: D

Source: Magoosh