It is very simple problem based on parallelism and isosceles triangle property concept.
Given things:
i) AB || CE
ii) angle (y) = 45 degree.
iii) CE = ED
Also, angle (y) + angle (ECD) + angle (CDE) = 180 degree.
Now as CE = ED, therefore angle (ECD) = angle (CDE), by the property of isosceles triangle.
Therefore, angle (ECD) = (180 - 45)/2 = 67.5 degree.
Now as AB || CE, therefore by parallel lines properties, angle (x) = 67.5
paper test geometry question
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