x^x = (10^100)^(10^100) = [ (10^100)^10 ] ^ 100
On paper it would looks something like that:
...........100
........10
...100
10
Since (a^b)^c = a^(b*c) we get: x^x = 10^(100*10*100), therefore k = 100,000
Edit: Answer is wrong, a^(b^c) != (a^b)^c
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PussInBoots
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sure
First X = 10^100
X^X = (10^100)^(10^100)
= (10^(10^2))^(10^100)
using the formula (a^m)^n = a^(m*n)
we get X^X = (10^((10^2)*10^100))
further simplifying the exponent ((a^m)*(a^n))= (a^(m+n)) we get X^X=10^(10^102)
Equating it to 10^K we get k = 10^102
First X = 10^100
X^X = (10^100)^(10^100)
= (10^(10^2))^(10^100)
using the formula (a^m)^n = a^(m*n)
we get X^X = (10^((10^2)*10^100))
further simplifying the exponent ((a^m)*(a^n))= (a^(m+n)) we get X^X=10^(10^102)
Equating it to 10^K we get k = 10^102
Aiming High
