A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person

[Vincen]

A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person will be the treasurer. In how many different ways can this be accomplished?

(A) 2

(B) 6

(C) 8

(D) 12

(E) 16

[spoiler]OA=D[/spoiler]

Source: Magoosh

[sahilaro23]

First select 2 people out of a group of 4 in '4C2' says = 6 ways.

Now here the stewed can come first and then comes the treasurer, or vice versa also possible so multiply this by 2 = 6x2 = 12 total ways. Hence D.

[Scott@TargetTestPrep]

A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person will be the treasurer. In how many different ways can this be accomplished?

(A) 2

(B) 6

(C) 8

(D) 12

(E) 16

[spoiler]OA=D[/spoiler]

Solution:

Since we have specific positions in the group, order matters, and so we have a permutation. Thus, the number of ways to select a steward and a treasurer from 4 employees is 4P2 = 4!/2! = 4 x 3 = 12 ways.

Answer: D