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All the employees of Company X were appraised at the year end. 40% of the employees got a...

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by BTGmoderatorLU » Wed Jul 15, 2020 10:52 am

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Source: e-GMAT

All the employees of Company X were appraised at the year end. 40% of the employees got a promotion, 50% of the employees got a salary hike and 30% of the employees neither got a promotion nor got a salary hike. If there were 40 employees who got both the promotion and the salary hike, what was the number of employees in the company?

A. 100
B. 120
C. 150
D. 200
E. 250

The OA is D
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Source: — Problem Solving |

BTGmoderatorLU wrote:
Wed Jul 15, 2020 10:52 am
Source: e-GMAT

All the employees of Company X were appraised at the year end. 40% of the employees got a promotion, 50% of the employees got a salary hike and 30% of the employees neither got a promotion nor got a salary hike. If there were 40 employees who got both the promotion and the salary hike, what was the number of employees in the company?

A. 100
B. 120
C. 150
D. 200
E. 250

The OA is D
Say there are 100 employees; thus, 100 – 30 = 70 got either promotion or salary hike or both.

=> 70 = #promotion + #Salary_hike – Both
=> 70 = 40 + 50 – Both

Both = 20%

Since 20% is 40 (given), or double, there must be 100*2 = 200 employees.

Correct answer: D

Hope this helps!

-Jay
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BTGmoderatorLU wrote:
Wed Jul 15, 2020 10:52 am
Source: e-GMAT

All the employees of Company X were appraised at the year end. 40% of the employees got a promotion, 50% of the employees got a salary hike and 30% of the employees neither got a promotion nor got a salary hike. If there were 40 employees who got both the promotion and the salary hike, what was the number of employees in the company?

A. 100
B. 120
C. 150
D. 200
E. 250

The OA is D
Solution:

We can let x = the total number of employees and create the equation:

#(Total) = #(Promotion) + #(Salary Hike) - #(Both) + #(Neither)

x = 0.4x + 0.5x - 40 + 0.3x

x = 1.2x - 40

40 = 0.2x

200 = x

Answer: D

Scott Woodbury-Stewart
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