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Source: — Data Sufficiency |

by CappyAA » Wed Oct 01, 2008 4:11 pm
Cannot solve with either (E)

(1) Avg score is 86 - This could be lots of students higher or lower. It doesn't tell about the number below 86. The only thing we know is that the average works out to 86. (NOT SUFFICIENT)
(2) Median is 86 - This says nothing about the average score. We do not know what the average is. We only know that the 18th person when listed in order scored an 86. (NOT SUFFICIENT)
(1) and (2) - We know that the median and average are both 86. If all students had different scores, we'd know that there would be 17 below the average. However, the 17th and 19th students in order could have also had an 86. (NOT SUFFICIENT)
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by krazy800 » Thu Oct 02, 2008 9:51 am
I would go with C.

Since information abt no. of students is given (i.e. 35) the median is 18th term. It is also given that median=average=86.. therefore 17 students score below average.. C is the answer.
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by Toph@GMAT_REBOOT » Thu Oct 02, 2008 11:51 am
It's E. As Cappy said, multiple people could be at the median. 35 people could have received an 86%, 1 person could have received an 86%, etc.
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by kris610 » Fri Oct 03, 2008 10:36 am
krazy800 wrote:I would go with C.

Since information abt no. of students is given (i.e. 35) the median is 18th term. It is also given that median=average=86.. therefore 17 students score below average.. C is the answer.
Median=Average iff the numbers are equally spaced..
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by namitrajiv » Sat Oct 04, 2008 12:53 pm
Please post the OA
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Nikhil - can you let us know the answer?

by arthi » Sun Oct 05, 2008 4:54 pm
I also think it is C
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by cramya » Sun Oct 05, 2008 5:31 pm
It should be E)

As a few others said there is no way of knowing what any of the students below the 18th student(median) got.

86 could have been repeated many times; we dont know.
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by arthi » Sun Oct 05, 2008 5:38 pm
But if the median and avg are the same, then the numbers should be equally spaced. so we should have 17 below avg.

Nikhil - what is the OA?
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