BTGModeratorVI wrote: ↑Tue May 12, 2020 2:12 pm
Is k^2 + k – 2 > 0?
(1) k is an integer greater than zero.
(2) k divided by 2 is an integer.
Answer:
C
Source: 800Score
Target question: Is k² + k – 2 > 0?
This is a good candidate for
rephrasing the target question.
What needs to happen in order for k² + k – 2 to be positive?
Factor to get: k² + k – 2 = (k + 2)(k - 1)
For (k + 2)(k - 1) to be positive, we need one of two scenarios:
Scenario A: (k + 2) and (k - 1) are both POSITIVE
For this to occur, k must be greater than 1
Scenario B: (k + 2) and (k - 1) are both NEGATIVE
For this to occur, k must be less than -2
In other words, for k² + k – 2 to be positive, it must be the case that EITHER k is greater than 1 OR k is less than -2
REPHRASED target question: Is it true that EITHER k is greater than 1, OR k is less than -2?
Once we've rephrased the target question, we can head to the two statements....
Statement 1: k is an integer greater than zero.
There are several values of k that satisfy statement 1. Here are two:
Case a: k = 2, in which case the answer to the REPHRASED target question is
YES
Case b: k = 1, in which case the answer to the REPHRASED target question is
NO
Since we cannot answer the
REPHRASED target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: k divided by 2 is an integer
There are several values of k that satisfy statement 2. Here are two:
Case a: k = 2, in which case the answer to the REPHRASED target question is
YES
Case b: k = 0, in which case the answer to the REPHRASED target question is
NO
Since we cannot answer the
REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined
Statement 1 tells us that k is positive
Statement 2 tells us that k divided by 2 is an integer.
In other words, k/2 must be a positive integer
Some possible values of k: 2, 4, 6, 8, . . .
In
all of these cases, the answer to the REPHRASED target question is
YES
Since we can answer the
REPHRASED target question with certainty, the combined statements are SUFFICIENT
Answer: C
Cheers,
Brent
