pappueshwar wrote:Machines X and Y run at different constant rates, and machine X can complete a certain job in 9 hours. Machine X worked on the job alone for the first 3 hours and the two machines, working together, then completed the job in 4 more hours. How many hours would it have taken machine Y, working alone, to complete the entire job?
18
13+1/2
7+1/5
4+1/2
3+2/3
OA IS A
Let the job = 36 units (the LCM of 9, 3 and 4).
Rate for X alone = w/t = 36/9 = 4 units per hour.
Work completed by X in 3 hours = r*t = 4*3 = 12 units.
Remaining work = 36-12 = 24 units.
Combined rate for X+Y to finish the job = w/t = 24/4 = 6 units per hour.
Thus, rate for Y alone = rate for X+Y - rate for X alone = 6-4 = 2 units per hour.
Time for Y to complete the job alone = w/r = 36/2 = 18 hours.
The correct answer is
A.
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