How many different subsets of the set {10, 14, 17, 24} are there that contain an odd number of elements?
(A) 3
(B) 6
(C) 8
(D) 10
(E) 12
OA is c
How can i get the correct answer here with well detailed explanation? please help me out Crying or Very sad
Thanks
Hi Roland2rule,
Let's take a look at your question.
The given set is: $$\left\{10,\ 14,\ 17,\ 24\right\}$$
The subsets that include odd number elements could have either one element or 3 elements. So let's first write all possible subsets that have only one element.
$$\left\{10\right\},\ \left\{14,\right\}\ \left\{17\right\},\left\{24\right\}$$
Therefore, there are 4 subsets that have one element.
Now let's write all possible subsets that have 3 elements.
$$\left\{10,\ 14,\ 17\right\},\ \left\{10,\ 14,\ 24\right\},\ \left\{10,\ 17,\ 24\right\},\ \left\{14,\ 17,\ 24\right\}$$
Therefore, there are 4 possible subsets of the given set that have 3 elements.
Hence the total number of subsets that have odd number of elements are 4 + 4 = 8.
So, Option
C is correct.
Hope it helps.
I am available if you'd like any follow up.
