A certain taxi company charges $ 3.10 for the first...

[BTGmoderatorLU]

A certain taxi company charges $ 3.10 for the first 1/5 of a mile plus $0.4 for each additional 1/5 of a mile. What would this company charge for a taxi ride that was 8 miles long?

A. $15.60
B. $16.00
C. $17.80
D. $18.70
E. $19.10

The OA is D.

I know that the solution should be Total($)= 3.10+0.4*(x/5), but I don't know how can I define the value of x, I don't understand.

Experts can you help with this PS question please? thanks!

[Jay@ManhattanReview]

A certain taxi company charges $ 3.10 for the first 1/5 of a mile plus $0.4 for each additional 1/5 of a mile. What would this company charge for a taxi ride that was 8 miles long?

A. $15.60
B. $16.00
C. $17.80
D. $18.70
E. $19.10

The OA is D.

I know that the solution should be Total($)= 3.10+0.4*(x/5), but I don't know how can I define the value of x, I don't understand.

Experts can you help with this PS question please? thanks!

You have to count how many 1/5s are there in 8 miles. It's simple, there are 8*5 = 40 numbers of 1/5s are there.

Thus, the total charge = 3.10 + 0.4*(40 - 1) = 3.10 + 0.4*40 - 0.4 = 3.10 + 16 - 0.4 = $18.70.

The correct answer: D

Hope this helps!

-Jay
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[Scott@TargetTestPrep]

A certain taxi company charges $ 3.10 for the first 1/5 of a mile plus $0.4 for each additional 1/5 of a mile. What would this company charge for a taxi ride that was 8 miles long?

A. $15.60
B. $16.00
C. $17.80
D. $18.70
E. $19.10

We know that for the first 1/5 mile of the 8-mile trip, the taxi company charges $3.10. For the next 7 4/5 miles, each 1/5 of a mile will cost $0.40. We need to find out how many 1/5s are in 7 4/5.

Since 7 4/5 = 39/5, there are 39 1/5s in 7 4/5. Therefore, the total cost of the 8-mile trip would be:

$3.10 + 39($0.40)

$3.10 + $15.60

$18.70

Answer: D