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by armaan700+ » Tue Jan 26, 2010 10:06 am
There are 3 red chips and 2 blue ones.
When arranged in a row, they form a certain color pattern, for example RBRRB. How many color patterns?

10
12
24
60
100
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Source: — Problem Solving |

by thephoenix » Tue Jan 26, 2010 10:33 am
= 5!/3!2!
= 10
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by Scott@TargetTestPrep » Sat Sep 21, 2019 11:09 am
armaan700+ wrote:There are 3 red chips and 2 blue ones.
When arranged in a row, they form a certain color pattern, for example RBRRB. How many color patterns?

10
12
24
60
100
The number of possible patterns is 5! / (3!*2!) = (5 x 4) / 2 = 10.

Alternate Solution:

Note that if the 5 chips were all of different colors, then we would have 5! = 120 different arrangements. But because there are 3 identical red chips and 2 identical blue chips, we must reduce the number of possible arrangements, using the indistinguishable permutations formula, obtaining 5! / (3!*2!) = (5x4) / (2x1) = 10.

Answer: A

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