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The dial shown above is divided into equal-sized intervals.

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by BTGmoderatorDC » Fri Jul 19, 2019 4:03 am

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The dial shown above is divided into equal-sized intervals. At which of the following letters will the pointer stop if it is rotated clockwise from S through 1,174 intervals?

(A) A
(B) B
(C) C
(D) D
(E) E

OA E

Source: Official Guide
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Source: — Problem Solving |

by swerve » Fri Jul 19, 2019 10:05 am
1174 rotations

Since there are 8 intervals \(\Rightarrow\) 1174 \(\Rightarrow\, 8k+6\)

So after 1168 rotations, the pointer will be back at \(S\)

And we just have to now rotate it 6 more times clockwise \(\Rightarrow\) It will land up at \(E\)

Hence, the answer is the option __E__
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by Darkknightreturning » Sun Jul 21, 2019 2:40 am
It will take the needle to reach to 8 intervals to reach the starting point.
Thus, 1174/8=1168 full circles and 6 intervals. Thus, the needle will be at E
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by Scott@TargetTestPrep » Tue Jul 30, 2019 8:41 am
BTGmoderatorDC wrote:Image

The dial shown above is divided into equal-sized intervals. At which of the following letters will the pointer stop if it is rotated clockwise from S through 1,174 intervals?

(A) A
(B) B
(C) C
(D) D
(E) E
We are given a diagram with 8 intervals of equal length. Let's start by sketching the diagram.

Image

Notice we have assigned a number to each letter marking between the intervals. Beginning with S = 0 and moving clockwise, we have A = 2, B = 3, C = 4, D = 5 and E = 6.

Let's first study the pattern of the spinner's movement. If the spinner were to go through just 8 intervals, it would stop where it started, at letter S. If, instead, it were to go through 10 intervals, it would go all the way around the circle one time (8 intervals) plus 2 more, stopping at letter A. One more example: if it were to go through 35 intervals it would make four complete revolutions, plus 3 more intervals, stopping at letter B. We can see that if we divide the total number of intervals it travels by 8, the whole number part of the quotient will be the number of revolutions it has made, and the remainder will tell us how many "extra" intervals it has gone past S before stopping.

Therefore, to determine at which letter the pointer will stop when it is rotated clockwise 1,174 intervals, we need to divide 1,174 by 8.

1,174/8 = 146 R 6.

The 146 indicates that the spinner has gone through 146 complete revolutions. The remainder 6 indicates that the spinner has stopped 6 intervals past S, which is location E.

Answer: E

Scott Woodbury-Stewart
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