Brent@GMATPrepNow wrote:j, k, m, x, y and z are positive integers. When j is divided by k, the remainder is m. When x is divided by y, the remainder is z. If ky = 75, which of the following CANNOT be the value of mz?
i) 49
ii) 50
iii) 56
A) iii only
B) i and ii
C) i and iii
D) ii and iii
E) i, ii and iii
Answer:
B
Source:
www.gmatprepnow.com
Difficulty level: 650-700
Useful remainder property:
When positive integer N is divided by positive integer D, the remainder R is such that 0 ≤ R < D
For example, if we divide some positive integer by 7, the remainder will be 6, 5, 4, 3, 2, 1, or 0
When j is divided by k, the remainder is m
The above
property tells us that
0 ≤ m < k
When x is divided by y, the remainder is z
The above
property tells us that
0 ≤ z < y
If ky = 75, which of the following CANNOT be the value of mz?
There are 3 ways in which ky = 75
1) k and y are 1 and 75
2) k and y are 3 and 25
3) k and y are 5 and 15
We can ELIMINATE case 1, because dividing by 1 will give us a remainder of 0, and we're told that all values are POSITIVE integers
So, k and y are EITHER 3 & 25 OR 5 & 15
So, we have two possible cases:
case a)
m < 3 and
k < 25
case b)
m < 5 and
k < 15
Now let's check the statements.
iii) 56
Are there values of m and z such that mz = 56, AND one of the two cases (above) are met?
YES!
If m = 4 and k = 14, then mk = (4)(14) = 56
This meets the conditions in case b. That is,
m < 5 and
k < 15
Since mz CAN equal 56, we can ELIMINATE answer choices A, C, D and E (since they say that mz CANNOT equal 56)
By the process of elimination, the correct answer is B
Cheers,
Brent
