gmat prep-probability

This topic has expert replies
Source: — Problem Solving |

Newbie | Next Rank: 10 Posts
Posts: 6
Joined: Wed Jan 10, 2007 6:57 am

by thegenius » Sun Sep 28, 2008 11:25 pm
Here you go...

P(E) = (Possible outcomes for E) / (Total possible outcomes)

Here,

We need to select 2 students, one from Junior class and one from Senior class. Also, The selected students should be a sibling pair, so,

First student from Junior Class can be selected in 60 ways (60 cos thats the total number of junior students in the sibling pair group).

Now, for each selected Junior student, the Senior student can be selected in exactly 1 way, because each pair is already defined. So for every Junior student selected, only one corresponding senior student can be selected for our event to have a possible outcome.

So Possible outcomes for event E = 60 x 1 = 60

Now total possible outcomes = 1000 (Number of ways of selecting Junior Student) x 800 (Number of ways of selecting Senior Student) = 800,000

P(E) = 60 / 800,000 = 3/40,000.

hence ans (A)

HTH
-TheGenius

Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pm
Thanked: 331 times
Followed by:11 members

by cramya » Mon Sep 29, 2008 7:01 pm
Another Approach:


Prob of selecting a sibling pair from Seniors = 60/800

Prob of selecting a sibling pair from Junior = 1/1000 (since there is only 1 sibling in the Juniors that would make a sibling pair from any one of the 60 siblings in the Seniors)

P(both) = 60/800 * 1/1000 = 3/40000

(OR)

Prob of selecting a sibling pair from Junior = 60/1000

Prob of selecting a sibling pair from Junior = 1/800 (since there is only 1 sibling in the Seniors that would make a sibling pair from any one of the 60 siblings in the Juniors )

P(both) = 60/1000 * 1/800 = 3/40000

User avatar
Master | Next Rank: 500 Posts
Posts: 435
Joined: Sat Sep 27, 2008 2:02 pm
Location: San Jose, CA
Thanked: 43 times
Followed by:1 members
GMAT Score:720

by dumb.doofus » Mon Sep 29, 2008 8:24 pm
cramya wrote:Another Approach:


Prob of selecting a sibling pair from Seniors = 60/800

Prob of selecting a sibling pair from Junior = 1/1000 (since there is only 1 sibling in the Juniors that would make a sibling pair from any one of the 60 siblings in the Seniors)

P(both) = 60/800 * 1/1000 = 3/40000

(OR)

Prob of selecting a sibling pair from Junior = 60/1000

Prob of selecting a sibling pair from Junior = 1/800 (since there is only 1 sibling in the Seniors that would make a sibling pair from any one of the 60 siblings in the Juniors )

P(both) = 60/1000 * 1/800 = 3/40000
nicely put buddy

Junior | Next Rank: 30 Posts
Posts: 18
Joined: Thu Jun 26, 2008 9:12 am

by xunil56 » Tue Sep 30, 2008 3:32 pm
cramya wrote:Another Approach:


Prob of selecting a sibling pair from Seniors = 60/800

Prob of selecting a sibling pair from Junior = 1/1000 (since there is only 1 sibling in the Juniors that would make a sibling pair from any one of the 60 siblings in the Seniors)

P(both) = 60/800 * 1/1000 = 3/40000

(OR)

Prob of selecting a sibling pair from Junior = 60/1000

Prob of selecting a sibling pair from Junior = 1/800 (since there is only 1 sibling in the Seniors that would make a sibling pair from any one of the 60 siblings in the Juniors )

P(both) = 60/1000 * 1/800 = 3/40000
Yep, that was cool.